Science
Section – A
Q.1. Why does the cord of an electric oven not glow while it’s heating element does?
Answer: The resistance of the heating element of an electric oven is very high. As the current flows through the heating element it becomes too hot and glows red. On the other hand the cord of an electric oven low resistance hence it does not become red during the flow of current.
Q.2. Although coal and petroleum are produced by the degradation of biomass, yet we need to conserve these resources. Why?
Answer: We need to conserve coal and petroleum because they are formed in millions of years and are non-renewable also and their rate of consumption is very high. So these are limited and cannot last for longer time.
Section – B
Q.3. What is atmospheric refraction? List two phenomena which can be explained on the basis of atmospheric refraction.
Answer: In atmosphere, there are layers of different densities and refractive indices, when the light ray is passed through these layers refraction of light takes place which is called atmospheric refraction.
Two phenomenon that can be explained on the basis of atmospheric refraction are:
- Twinkling of stars.
- Early sunset and delayed sunrise.
Q.4. Name a metal of medium reactivity and write three main steps in the extraction of this metal from its sulphide ore.
Answer: Zinc
The steps involved in the extraction of zinc from zinc sulphide are:
1. Roasting of sulphide ore in the presence of air to convert it into metal oxide.
2. Reduction of metal oxide with carbon to get free metal.
3. Refining of impure metal to get pure metal.
Q.5. List two chemical properties on the basis of which ethanol and ethanoic acid may be differentiated and explain how.
OR
Q.5. Unsaturated hydrocarbons contain multiple bonds between two carbon atoms and these compounds show addition reactions. Out of saturated and unsaturated carbon compounds, which compounds are more reactive? Write a test to distinguish ethane from ethene.
Answer: 1. Ethanol does not react with sodium bicarbonate but ethanoic acid reacts with sodium bicarbonate releasing CO2 gas.
2. Ethanol does not change the colour of blue litmus paper but ethanoic acid changes the colour of blue litmus to red due to presence of carboxylic acid group.
OR
Answer: Unsaturated carbon compounds are more reactive than saturated carbon compounds. Bromine water is decolourized by ethene but there is no change of colour of bromine water with ethane.
Section – C
Q.6. What happens to a beam of white light when it gets refracted through a glass prism? Which colour deviates the most and the least after refraction through a prism? What is likely to happen if a second identical prism is placed in an inverted position with respect to the first prism. Justify your answer.
OR
Q.6. A student needs spectacles of power -0.5 D for the correction of his vision.
(i) Name the defect in vision the student is suffering from.
(ii) Find the nature and focal length of the corrective lens.
(iii) List two causes of this defect.
Answer: When white light is refracted through a glass prism, it gets split into its constituting colours at different angles. This phenomenon is called Dispersion of Light.
Forming a rainbow,
Least deviated colour is red whereas most deviated colour is violet.
When second identical prism is placed in an inverted position with respect to first prism, recombination of the spectrum will take place and white light will be obtained.
OR
Answer: (i) Myopia.
(ii) Concave lens with the focal length of 200 cm
Given, P = -0.5 D
We have,
P = 1/f
f=1/P
f= 1/(-0.5)
f= -2m = -200cm
(iii) Two causes of Myopia are:
- Elongation of eye ball.
- High converging power of eyeless.
Q.7. Define a food chain. Design a terrestrial food chain of four trophic levels. If a pollutant enters at the producer level, the organisms of which trophic level will have the maximum concentration of the pollutant in their bodies? What is this phenomenon called?
Answer: It is the sequence of arrangement of a living organism in a community in which one organism consumes another organism to transfer food energy.
Grass → Insect → Frog → Bird
The organism at a higher tropic level will have a maximum concentration of pollutants. This phenomenon is called biological magnification.
Q.8. What are amphoteric oxides? Give an example. Write balanced chemical equations to justify your answer.
Answer: Those oxides which behave both acidic and basic oxides are called amphoteric oxides. Example: Al2O3 (Alumina)
Q.9. During the reaction of some metals with dilute hydrochloric acid, the following observations were made by a student:
(a) Silver does not show any change.
(b) Some bubbles of gas are seen when a lead is reacted with the acid.
(c) The reaction of sodium is found to be highly explosive.
(d) The temperature of the reaction mixture rises when aluminium is added to the acid.
Explain these observations giving an appropriate reason.
Answer:
(a) Silver is covered with a thin layer of silver chloride, so it does not react with dilute hydrochloric acid.
(b) Bubbles of hydrogen gas are evolved when lead is reacted with the acid.
(c) The reaction of sodium is found to be highly explosive because sodium is very reactive in nature.
(d) The temperature of the reaction mixture rises when aluminium is added to the acid because the reaction is highly exothermic in nature.
Q.10. Given below are the steps for the extraction of copper from its ore. Write the chemical equation of the reactions involved in each case.
(i) Roasting of copper (I) sulphide.
(ii) Reduction of copper (I) oxide from copper (I) sulphide
(iii) Electrolytic refining.
Answer:
Q.11. What is transpiration? List its two functions.
OR
Q.11. (a) What is translocation? Why is it essential for plants?
(b) Where do the substances in plants reach as a result of translocation?
Answer: The evaporation of water from the leaves of a plant is called transpiration. Functions of transpiration
1. It helps in the upward movement of water and minerals from the root to the leaves through the stem.
2. Helps in cooling the plant surface.
OR
Answer: (a) The transport of food from leaves to other parts of the plant is called translocation. Translocation is essential for plants because without it food prepared by the leaves cannot reach other parts of the plant for their growth and development.
(b) The substances in plants reach other tissues in plants from the leaves as a result of translocation.
Q.12 What is carpel? Write the function of its various parts.
Answer: The flask-shaped organ in the centre of a flower is called carpel. It is also called a female reproductive organ of the plant. It is made up of three parts:
1. Stigma
2. Style
3. Ovary
1. Stigma is the top part of carpel and is sticky. So, it receives the pollen from the anther of stamen.
2. Style connects stigma to ovary.
3. Ovary contains female gametes of the plant and helps in reproduction.
Q.13 A student holding a mirror in his hand directed the reflecting surface of the mirror towards the Sun. He then directed the reflected light on to a sheet of paper held close to the mirror.
(a) What should he do to bum the paper?
(b) Which type of mirror does he have?
(c) Will he be able to determine the approximate value of the focal length of this mirror from this activity ? Give reason and draw ray diagram to justify your answer in this case.
OR
Q.13. A 10 cm tall object is placed perpendicular to the principal axis of a convex lens of focal length 12 cm. The distance of the object from the lens is 18 cm. Find the nature, position and size of the image formed.
Answer: (a) He should place the sheet of paper at the focus of the mirror to burn the paper.
(b) He has a concave mirror.
(c) Yes, the sheet of paper will start burning at the focus of the mirror which will give an approximate value of focal length, i.e., the distance between the mirror and the point where the sheet of paper starts burning.
OR
Answer: A concave mirror forms a real image of the sun,
Given: Height of object, h1 = +10 cm. Focal length, f = +12 cm.
Object distance, u = -18 cm. From the lens formula,
The position of image formed is at distance of 36 cm from convex lens. Since the value of the magnification is more than 1 (it is 2), the image formed is larger than object. The minus sign of magnification shows that image is formed below the principal axis. Hence, the image formed is real and inverted,
Q.14 What are solar cells? Explain the structure of solar panel. List two principal advantages associated with solar cells.
Answer: Solar cells are the devices which convert solar energy into electricity. A simple solar cell is made up of a sandwich of a silicon-boron layer and a silicon-arsenic layer. Boron and arsenic are present in a very small amount. A piece of wire is soldered into the top of the upper layer of cell and another piece of wire is soldered at the bottom of the lower layer to pass on the current. The solar cell is covered with a glass cover for protection. Advantages:
• Solar cells have no moving parts.
• It requires no maintenance.
Q.15. (a) Budding, fragmentation and regeneration, all are considered as an asexual mode of reproduction. Why?
(b) With the help of neat diagrams, explain the process of regeneration in Planaria.
Answer: (a) Budding, fragmentation and regeneration are considered as an asexual mode of reproduction because only one parent is involved no sex cells are involved.
(b) Regeneration in planaria.
The process of getting back a full organism from its body parts is called regeneration. Planaria reproduces by this method in which if the body of Planaria somehow gets cut into a number of pieces, then each body piece can regenerate into a complete Planaria by growing all the missing parts.
Section – D
Q.16. A 6 cm tall object is placed perpendicular to the principal axis of a concave mirror of focal length 30 cm. The distance of the object from the mirror is 45 cm. Use mirror formula to determine the position, nature and size of the image formed. Also, draw labelled ray diagram to show the image formation in this case.
OR
Q.16. An object 6 cm in size is placed at 50 cm in front of a convex lens of focal length 30 cm. At what distance from the lens should a screen be placed in order to obtain a sharp image of the object? Find the nature and size of the image. Also, draw a labelled ray diagram to show the image formation in this case.
Answer: Given, Height of the object = 6 cm
Focal length, f = -30 cm
Object distance, u = -45 cm
Image distance, v = ?
Height of image, hi = ?
We have,
1/f = 1/v + 1/u
Hence, the image formed is virtual, erect and magnified.
Q.17. (a) Why is the use of iodised salt advisable? Name the disease caused due to deficiency of iodine in our diet and state its one symptom.
(b) How do nerve impulses travel in the body? Explain.
OR
Q.17. What is hydrotropism? Design an experiment to demonstrate this phenomenon.
Answer: (a) lodised salt is advisable because iodine is necessary for the formation of thyroxine hormone by the thyroid gland Goitre is the disease caused due to its deficiency. Symptom: The neck of the person appears to be swollen due to the enlargement of thyroid gland.
(b) Two neurons are not joined to one another completely. There is a small gap between a pair of neuron. This gap is called synapse. The nerve impulse are carried out to this gap by the help of neurotransmitter (chemical substance). The conduction of nerve impulse through the synapse takes place in the form of electrical nerve impulse. When a stimulus acts on the receptor an electrical impulse is produced with the help of chemical reaction. This electrical impulse passes through the synapse and then to the other neuron. Thus, in this way nerve impulses travel in the body.
OR
Answer: The movement of root of plants towards water is called hydrotropism. Take two glass troughs A and B fill each one of them two-thirds with soil. In trough A plant a tiny seedling figure
(a). In trough B plant a similar seedling and also place a small clay pot inside the soil figure
(b). Water the soil in trough A daily and uniformly. Do not water the soil in trough B but put some water in the clay pot buried in the soil. Leave both the troughs for a few days.
Now, dig up the seedlings carefully from both the trough without damaging their roots. We will find that the root of seedling in through A is straight. On the other hand, the root of seedling in trough B is found to be bent to the right side (towards the clay pot containing water) figure (b). This can be explained as follows.
In through A, the root of seedling gets water from both sides (because the soil is watered uniformly) in trough B, the roots gets water oozing out from the clay pot which is kept on the right side. So, the root of seedling in trough B grows and bends towards the source of water to the right side. The experiment shows that the root of a plant grows towards water. In other words, the root of a plant is positively hydrotropic.
Q.18. (a) What are homologous structures ? Give an example.
(b) “The sex of a newborn child is a matter of chance and none of the parents may be considered responsible for it.” justify this statement with the help of a flow chart showing sex-determination in human beings.
Answer: (a) The structures which have the same basic design but different functions are called homologous structures or homologous organs. Example: Forelimbs of a man, a lizard, a frog they have same basic design of bones but perform different functions. (b) The sex of a newborn depends on what happens at the time of fertilization.
1. If a sperm carrying X chromosome fertilizes the ovum carrying X chromosome, then the girl child will be born and the child will have XX combination of sex chromosomes.
2. If a sperm carrying Y chromosome fertilizes the ovum carrying X chromosome, then the child born will be.
The above presentation clearly shows that it is matter of chance whether the newborn will be boy or girl and none of the parents may be considered responsible for it.
Q.19. When do we consider a person to be myopic or hypermetropic ?
List two causes of -hypermetropia.
Explain using ray diagrams how the defect associated with hypermetropic eye can be corrected.
Answer: Myopia is the defect in vision in which a person cannot see the distant objects clearly whereas in hypermetropia is the defect in which a person cannot see nearby objects clearly. Hypermetropia is caused due to:
1. Decrease in converging power of eye-lens.
2. Too short eye ball.
In a hypermetropic eye, the image of near by object lying at normal near point N (at 25 cm) is formed behind the retina.
Hypermetropic eye can be corrected using convex lenses. When a convex lens of suitable power is placed in front of hypermetropic eye, then the diverging rays of light from the object are converged first by the convex lens used. This form a virtual image of the object at another near point N’. Now, the rays can be easily focused by the eye lens to form an image on retina.
Q.20. What is sexual reproduction?
Explain how this mode of reproduction gives rise to more viable variations than asexual reproduction.
How does this affect evolution?
Answer: The production of new organisms from two parents by making use of their sex cells is called sexual reproduction.
In sexual reproduction, more viable variations are observed than asexual reproduction as two parents is involved. In the case of asexual reproduction single parent organism gives rise to offsprings which are genetically identical to their parents. This limits the scope of variation in characters of offsprings. Due to sexual reproduction, the extent of variation is much large and therefore choices of evolution is also high.
The variations in the characters of the obtained offsprings from sexual reproduction enable them to adapt according to the environment and struggle for their existence. Over a period of time, the characters accumulate within the species and the formed species give rise to new species and this process goes on.
Q.21. Draw the paitern of magnetic field lines produced around a current-carrying straight conductor passing perpendicularly through horizontal cardboard. State and apply the right-hand thumb rule to mark the direction of the field lines. How will the strength of the magnetic field change when the point where magnetic field is to be determined is moved away from the straight conductor ?
Give reason to justify your answer.
Answer: Maxwell’s Right Hand Thumb rule states that if the current-carrying wire is imagined to be held in the right hand so that thumb points in the direction of current, then the direction in which fingers encircle the wire will give the direction of magnetic field lines around the wire. If we hold the current-carrying straight wire so that thumbs Magnetic field pattern due to a straight current-carrying wire in upward direction points the direction of current, the direction of magnetic field lines will be anticlockwise. The strength of the magnetic field is inversely proportional to the distance of the point of observation from the wire So, as we move away from the wire the strength of magnetic decreases Current (upwards).
Section – E
Q.22. A teacher provided acetic acid, water, lemon juice, aqueous solution of sodium hydrogen carbonate and sodium hydroxide to students in the school laboratory to determine the pH values of these substances using pH papers. One of the students reported the pH values of the given substances as 3, 12, 4, 8 and 14 respectively. Which one of these values is not correct? Write its correct value stating the reason.
OR
Q.22. What would a student report nearly after 30 minutes of placing duly cleaned strips of aluminium, copper, iron and zinc in freshly prepared iron sulphate solution taken in four beakers?
Answer: The value of pH for water is not correct. The correct value of pH of water is 7 because it has almost equal concentration of H+and OH–, due to which it is neutral.
OR
Answer: Aluminium displaces the iron from iron sulphate and the colour of two solution changes from green to brown. No change takes place when copper strip is dipped in iron sulphate solution. No cfiange will be observed when iron strips are dipped in iron sulphate solution. The colour of the solution changes from green to colourless when zinc is added to iron sulphate solution.
Q.23 What is observed when a pinch of sodium hydrogen carbonate is added to 2 mL of acetic acid taken in a test tube? Write chemical equation for the reaction involved in this case.
Answer: CO2 gas is evolved with brisk effervescence when sodium hydrogen carbonate is added to acetic acid.
Q.24. List in proper sequence four steps of obtaining germinating dicot seeds.
OR
Q.24. After examining a prepared slide under the high power of a compound microscope, a student concludes that the given slide shows the various stages of binary fission in a unicellular organism. Write two observations on the basis of which such a conclusion may be drawn.
Answer: 1. The root is formed when radicle of seed grows.
2. The root grows downward into the soil and absorbs water and minerals from the soil.
3. The shoot is formed from the upward growth of plumule.
4. The green leaves are developed when the shoot comes above the ground.
OR
Answer: 1. A single parent divides to form two daughter cells.
2. The nucleus of mature cell seems elongated and a grove is formed in cell which divides the nucleus.
Q.25. List four precautions which a student should observe while preparing a temporary mount of a leaf peel to show stomata in his school laboratory.
Answer: 1. Freshly plucked leaf should be taken for an epidermal peel.
2. Hold the slide by its edges.
3. Peel should be cut to a proper size.
4. The peel should be allowed to dry.
Q.26. Draw the path of a ray of light when it enters one of the faces of a glass slab at an angle of nearly 45°. Label
(i) angle of refraction
(ii) angle of emergence and
(ii) lateral displacement.
OR
Q.26. A student traces the path of a ray of light through a glass prism as shown in the diagram, but leaves it incomplete and unlabelled. Redraw and complete the diagram. Also label on it zi, ze, zr, and ZD.
Answer:
Q.27. The current flowing through a resistor connected in a circuit and the potential difference developed across its ends are as shown in the diagram by milliammeter and voltmeter readings respectively:
(a) What are the least counts of these meters?
(b) What is the resistance of the resistor?
Answer: (a) 10 mA and 0.1 V
(b) V = 2.4 volt, 1 = 250 mA = 0.25 A
From Ohm’s law.
R=v/I = 2.4/0.25 = 9.6Ω